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Gemini 3.6 Flash vs Qwen3.7 Plus

vs

什么时候选哪个

当音频是输入的一部分时选 gemini-3.6-flash:它接受文本、图像、视频和音频(音频输入每百万 token $5,音频缓存读取 $0.5),上下文窗口 1048576 token。以更低成本做文本、图像和视频工作时选 qwen3.7-plus——输入 $0.4、输出 $1.6,对比 $1.5 和 $7.5,约便宜 3.75 倍和 4.7 倍——上下文 1000000 token,最大输出同为 65536。Qwen3.7 Plus 还允许关闭思考,并标记了推理和长上下文,而 Gemini 3.6 Flash 始终在思考。

Benchmark 成绩

高于同类均值无更高分Gemini 3.6 Flash6 / 191 / 19Qwen3.7 Plus11 / 244 / 24
Gemini 3.6 Flash Qwen3.7 Plus 其他参测模型 同类均值 ★ 没有模型得分更高
DeepSWE 1.1
48.6%
16.5%
BioMysteryBench hard
41.2%
N/A
OSWorld 2.0
33.8%
N/A
JobBench
N/A
27.6%
Harvey Lab-AA
85.1%
N/A
GPQA Diamond
N/A
90.3%
ERQA
N/A
69.8%
Agents' Last Exam Pass
24.2%
13.2%
LVBench
84.2%
76.2%

供应商公布: Alibaba (Qwen) Anthropic ByteDance DeepSeek Google MiniMax Moonshot OpenAI Tencent Z.ai

价格

Gemini 3.6 Flash Qwen3.7 Plus Δ
输入 / 1M token $1.5 $0.4 3.8×
输出 / 1M token $7.5 $1.6 4.7×
缓存读取 / 1M token $0.15 $0.08 1.9×
缓存写入 - 1.25x -

价格取自构建时的实时目录,最新价格见各模型页面。

两个模型所处的位置:全部 76 个按同一单位计费的聊天模型的每 1M token 输入价分布(对数刻度)

Gemini 3.6 Flash · $1.5 Qwen3.7 Plus · $0.4
$0.05 · Qwen3 VL Flash $30 · GPT-5.4 Pro

能力

Gemini 3.6 Flash Qwen3.7 Plus
工具调用 是 是
思考控制 始终开启 可配置
结构化输出 是 是
提示词缓存 隐式 + 显式 隐式 + 显式
缓存有效期 未公布 explicit: 5m, reset on hit
最小缓存前缀 4096 个 token 1024 个 token

规格

Gemini 3.6 Flash Qwen3.7 Plus
输入模态 文本 图像 音频 视频 文本 图像 视频
输出模态 文本 文本
发布日期 2026-07-21 2026-06-01
知识截止日期 2026-03 -
上下文窗口 1M 1M
最大输出 66K 66K
思考参数 thinkingLevel
  • enable_thinking
  • thinking_budget
  • preserve_thinking
可选值
  • minimal
  • low
  • medium
  • high
enable_thinking
  • true
  • false
thinking_budget
  • in tokens
preserve_thinking
  • true
  • false
默认值 medium

on

the Qwen3.7 Plus series is hybrid thinking with thinking enabled by default, and preserve_thinking is off

规格照录自各供应商的文档;供应商没有公布的项目,对应的行直接省略,不做推断。 完整来源: Gemini 3.6 Flash · Qwen3.7 Plus

同一条提示词,两个模型,经网关实测

提示词 Explain to a CFO, in exactly three sentences, why our LLM bill doubled after we enabled reasoning. 检查 恰好 3 句

Gemini 3.6 Flash 通过 · 3 sentences

Enabling reasoning causes the model to generate thousands of internal "thinking" tokens behind the scenes to process logic before delivering the final response. Because our vendor bills us for every token generated—including these intermediate processing steps—our billable output volume per query surged significantly. Since output tokens carry a much higher unit cost than input tokens, this jump in processing volume directly doubled our overall spend.

输出 893 tok (+816 思考) 延迟 4.7 s

Qwen3.7 Plus 通过 · 3 sentences

Enabling reasoning requires the model to generate extensive internal "thinking" tokens to process complex logic before delivering a final answer. Because our vendor charges us per token consumed, this hidden computational overhead effectively doubles our output volume for the exact same number of user requests. Consequently, our costs have doubled because we are now paying for the model's increased processing time to achieve higher-quality, more accurate results.

输出 1428 tok (+1345 思考) 延迟 25.2 s

指令遵循(恰好三句,数得出来)、受众适配(对 CFO 说话的口吻),以及下方 token 计数暴露出的隐藏思考计费差额。

提示词 This function is supposed to return the longest run of consecutive equal items, but callers report it is off by one on single-element inputs and misses runs that end at the last index. Fix it and explain the bug in one paragraph. 检查 修复通过测试

Gemini 3.6 Flash 通过 · 8/8 cases

Here is the fixed function along with an explanation of the bugs: ```python def longest_run(xs): if not xs: return 0 best = 1 cur = 1 for i in range(1, len(xs)): if xs[i] == xs[i - 1]: cur += 1 else: cur = 1 best = max(best, cur) return best ``` ### Explanation The original function initialized `cur` and `best` to `0` and incremented `cur` on matching adjacent items, which meant it was counting identical adjacent *pairs* rather than the total number of *elements* in a run. This caused single-element inputs to skip the loop and return `0` instead of `1`, and undercounted all run lengths by 1 (for example, a run of two items at the end of the list resulted in `cur = 1`). […]

输出 2034 tok (+1768 思考) 延迟 10.0 s

Qwen3.7 Plus 通过 · 8/8 cases

## Fixed Code ```python def longest_run(xs): if not xs: return 0 best = 1 cur = 1 for i in range(1, len(xs)): if xs[i] == xs[i - 1]: cur += 1 else: cur = 1 best = max(best, cur) return best ``` ## Bug Explanation The function has two related bugs rooted in how it counts run lengths. First, `cur` is initialized to `0` and only incremented on matches, so it counts the number of *transitions* between equal elements rather than the total elements in the run—a run of N identical items only reaches `cur = N − 1`, undercounting by one. This also causes the single-element case to return `0`, since the loop never executes and `cur` never increments. […]

输出 2317 tok (+2005 思考) 延迟 40.5 s

修复是否真的正确(能运行)、解释的信息密度,以及在一个范围明确的任务上的 token 效率。

提示词 Extract a JSON object with fields {company, quarter, revenue_usd_m, growth_pct, guidance} from this text. Use null for anything not stated; add no other fields. 检查 合法 JSON,严格符合 schema

Gemini 3.6 Flash 通过 · 5/5 fields, guidance "withheld"

```json { "company": "Meridian Robotics", "quarter": "September quarter", "revenue_usd_m": 412, "growth_pct": null, "guidance": "withheld" } ```

输出 2843 tok (+2783 思考) 延迟 13.1 s

Qwen3.7 Plus 通过 · 5/5 fields, guidance null

{ "company": "Meridian Robotics", "quarter": "September", "revenue_usd_m": 412, "growth_pct": 11, "guidance": null }

输出 1807 tok (+1750 思考) 延迟 31.6 s

是否严守 schema(不臆造字段)、能否顶住幻觉压力(原文明说暂不给出 guidance),以及结构化输出路径的差异。

提示词 Write a 120-word product announcement for an API gateway feature that caches prompts across providers. Forbidden words: "seamless", "unlock", "game-changer", "revolutionize", "empower". Exactly one sentence must be a question. 检查 120 词,0 个禁用词

Gemini 3.6 Flash 未通过 · 60 words, 0 banned, 0 questions

72: reducing 73: your 74: monthly 75: token 76: spend. S6 (21): 77: You 78: can 79: easily 80: set 81: custom 82: expiration 83: rules, 84: configure 85: TTL 86: settings, 87: and 88: manage 89: cache 90: invalidation 91: across 92: all 93: vendors 94: from 95: one 96: centralized 97: dashboard. S7 (23): 98: Start 99: optimizing […]

输出 4092 tok (+3929 思考) 延迟 16.3 s

Qwen3.7 Plus 通过 · 120 words, 0 banned, 1 question

Introducing PromptCache, our new API gateway feature designed to store and reuse prompts across multiple artificial intelligence providers. Have you ever noticed how repeatedly sending identical queries drains your budget and increases latency? PromptCache solves this by intelligently storing responses at the gateway level. When your application requests the same prompt from a different provider, the system instantly returns the cached result. This drastically reduces API costs and accelerates response times for your users. You can configure custom expiration times and set specific fallback rules for each vendor. You must stop paying twice for the exact same computation. Please upgrade your entire infrastructure today and experience much faster and cheaper integrations without changing a single line of your application code.

输出 4453 tok (+4312 思考) 延迟 76.8 s

是否守住约束(字数预算、禁用词表、只能有一个问句)、文风特征,以及长度控制。

改一行代码就能在两个模型之间切换

下方每个标签页里都有两个模型 ID,高亮的那两行是唯一要改的地方。端点不变,API key 不变,请求结构也不变。

from openai import OpenAI

client = OpenAI(
    base_url="https://synthorai.io/v1",
    api_key="sk-syn-...",
)

resp = client.chat.completions.create(
    model="gemini-3.6-flash",
    # model="qwen3.7-plus",  # 取消注释此行,注释上一行
    messages=[{"role": "user", "content": "Summarize this diff"}],
)
print(resp.choices[0].message.content)

获取 API key →

常见问题

Gemini 3.6 Flash 和 Qwen3.7 Plus 哪个更便宜?

按「输入 / 1M token」算,Qwen3.7 Plus 更便宜($0.4 对 $1.5,相差 3.8×)。其他计费项的结论可能相反,完整价格见上方表格,实际成本取决于你的用量构成。

不用分别集成两次,就能对 Gemini 3.6 Flash 和 Qwen3.7 Plus 做 A/B 测试吗?

可以。两个模型走同一个 OpenAI 兼容端点,用同一个 API key,切换时只要改一行里的模型名,所以可以给两个模型各分一部分流量,直接对比账单。

Gemini 3.6 Flash 和 Qwen3.7 Plus 支持提示词缓存吗?

支持。两个模型的缓存读取价都低于各自的输入价,所以前缀能反复命中缓存的负载,实际成本会比按官网价估算的低。具体的缓存读取价见上方价格表。

相关对比

我们的实测研究